Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. Four percent of the panels from Plant A and 1% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 2%?

Respuesta :

Answer:

The answer is "16,000"

Step-by-step explanation:

In this question the amounts of panels created by B the x.

[tex]\therefore[/tex]

Calculating the amounts of defective panels from B:

[tex]\to \frac{1}{100} \times x = 0.01x[/tex]

Calculating the amounts of defective panels from A:

[tex]\to \frac{4}{100} \times 8000 = 320[/tex]

Calculating the total defective panels are :

[tex]\to 320+ 0.01x[/tex]

Calculating the total panels manufactured:

[tex]\to 8000 + x[/tex]

when the overall percentage of the defective panels is [tex]2\%[/tex]

[tex]\to \frac{(320 + 0.01x)}{(8000 + x)} = 0.02\\\\\to (320 + 0.01x) = 0.02 (8000 + x)\\\\\to 320 + 0.01x = 160 + 0.02x\\\\\to 320 -160 = -0.01x + 0.02x\\\to 160 = 0.01x\\\\\to x=\frac{160}{0.01}\\\\\to x=16,000\\\\[/tex]