mdhoang2003 mdhoang2003

22-07-2021
Chemistry

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30 POINTS!! Will mark brainliest if correct answer and all work is shown! What mass in grams of tin would be required to completely react with 1.30 L of 0.750 M HBr in the following chemical reaction? Sn(s) + 4 HBr(aq) → SnBr₄ (aq) + 2 H₂ (g)

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HuyMaiSweetie HuyMaiSweetie

23-07-2021

Answer:

mSn=0.24375*59=14.38125

Explanation:

nHBr=1.3*0.75=0.975

nSn=1/4nHBR=0.975/4=0.24375

mSn=0.24375*59=14.38125

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