Answer: [tex]37.4\ m[/tex]
Step-by-step explanation:
Given length of shadow [tex]l=55\ m[/tex]
Hill inclination [tex]21.4^{\circ}[/tex]
Angle of elevation for sun [tex]48.3^{\circ}[/tex]
Suppose the length of the pole is [tex]h[/tex]
from the figure, and using sine rule. It can written
[tex]\Rightarrow \dfrac{55}{\sin 41.7^{\circ}}=\dfrac{h}{\sin 26.9^{\circ}}\\\\\Rightarrow h=55\cdot\dfrac{\sin 26.9^{\circ}}{\sin 41.7^{\circ}}\\\\\Rightarrow h=55\cdot 0.68011\\\Rightarrow h=37.40\ m[/tex]
