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During the 5 minute period described in question 4, the water in the insulated vessel undergoes a temperature increase of 20 C. Assuming all of the electrical energy dissipated by the resistor was transferred to the water as heat, what is the mass of the water

Respuesta :

Answer:

Please find the complete question in the attached file.

Explanation:

[tex]V=12\ V\\\\I=1.2\ A\\\\T=5\times 60=300\ second\\\\[/tex]

Calculating the electrical energy dissipated:

[tex]w=p\cdot t=V\cdot I \cdot t\\\\[/tex]

              [tex]=12\times 1.2 \times 300 \ J\\\\=4320\ J[/tex]

[tex]\Delta T=20^{\circ}\ C\\\\W=m\cdot c\cdot \Delta T\\\\4320=m(4186 \times 20)\\\\m=\frac{4320}{4186 \times 20}=51.6 \ grams=0.516 \ kg\\\\[/tex]

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