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Balance the redox reaction by oxidation number or ion electron method and indicate oxidizing and reducing agent . KMno4 + KBr + H2SO4 approach K2SO4 + MnSO4 + H2O + Br2​

Respuesta :

rose9374

Answer:

2KMnO₄ (aq) + 10KBr (aq) + 8H₂SO₄ (aq) -> 2MnSO₄ (aq) + 5Br₂ (aq) + 6K₂SO₄ (aq) + 8H₂O (l)

oxidizing agent = KMnO₄

reducing agent = KBr

Explanation:

KMnO₄ -> 2Mn⁷⁺ + 10e⁻ = 2Mn²⁺

KBr -> 10Br⁻⁺ - 10e⁻ = 10Br⁰

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