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The population of a strain of bacteria doubles in a culture. At noon there were 80 bacteria present and by 4:00 PM there were 20 480 bacteria. Determine algebraically the doubling period. Hint: You DO NOT need to use systematic trials.

Respuesta :

Answer:

t = 1/2 hour

Step-by-step explanation:

20480 = 80[tex]x^{t }[/tex]

20480 = 80[tex]x^{4 }[/tex]

20480/80  =  [tex]x^{4 }[/tex]

256 =  [tex]x^{4 }[/tex]

x = 4

doubling period

2 = [tex]4^{t}[/tex]

t = 1/2 hour

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