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Calculate the elastic energy stored up in a wire originally 5 meter​
long and 10^-3 m in diameter which has been stretched by 3×10^-4 m due to a load of 10 kg.

Respuesta :

Numenius

Answer:

The elastic energy is 245 J.

Explanation:

Length, L = 5 m

Diameter, D = 10^-3 m

Stretch, l = 3 x 10^-4 m

Load, F = 10 x 9.8 = 98 N

Let the elastic energy is U.

[tex]U = \frac{1}{2}\times stress\times strain\times volume\\\\U = 0.5\times \frac{Force}{area}\times \frac{l}{L}\times Area\times L\\\\U = 0.5 \times F\times l\\\\U = 0.5\times 98\times 5\\\\U = 245 J[/tex]

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