The measure of the side of a triangle AC is [tex]16\sqrt{2}[/tex] cm.
Given that, ∠45° and AB=16 cm.
We need to find the measure of side AC.
How do use trigonometric ratios to find the measure of the sides of a triangle?
There are three steps:
- Choose which trigonometric ratio to use. Choose either sin, cos, or tan by determining which side you know and which side you are looking for.
- Substitute your information into the trigonometric ratio.
- Solve the resulting equation to find the length of the side.
Now, [tex]sin \ C=\frac{AB}{AC}[/tex] (∵ sinα=Opposite/Hypotenuse)
[tex]sin 45^{o} =\frac{16}{AC} \\[/tex]
[tex]\implies \frac{1}{\sqrt{2} } =\frac{16}{AC}[/tex]
[tex]\implies AC=16\sqrt{2}[/tex] cm
Therefore, the measure of the side of a triangle AC is [tex]16\sqrt{2}[/tex] cm.
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