Answer:
Solution given:
Sin[tex]\theta_{1}=\frac{-\sqrt{3}}{2}[/tex]
[tex]\frac{opposite}{hypotenuse}=\frac{-\sqrt{3}}{2}[/tex]
equating corresponding value
opposite=-[tex]\sqrt{3}[/tex]
hypoyenuse=2
adjacent=x
By using Pythagoras law
hypotenuse²=opposite²+adjacent²
2²=-[tex]\sqrt{3²}[/tex]+x²
4=3+x²
x²=4-3
x=[tex]\sqrt{1}=1[/tex]
x=-1
In third quadrant
Cos angle is negative
Cos[tex]\theta_{1}=\frac{-adjacent}{hypotenuse}[/tex]
Cos[tex]\theta_{1}=\frac{-1}{2}[/tex]
