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[tex]\frac{x+4}{2} -\frac{3}{x-3} =1[/tex]

Quadratics null factor the given answer is x= 4,−3 but I don't know how to work it out

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don1522
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Answer:

Hello,

Step-by-step explanation:

[tex]x\neq 3\\\\\dfrac{x+4}{2} -\dfrac{3}{x-3} =1\\\\\dfrac{(x+4)(x-3)-2*3-2(x-3)}{2(x-3)} =0\\\\x^2+4x-3x-12-6-2x+6=0\\\\x^2-x-12=0\\\\x^2-4x+3x-12=0\\\\x(x-4)+3(x-4)=0\\\\(x-4)(x+3)=0\\\\x=4\ or\ x=-3\\[/tex]

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