Help with Maths Laws of Indices
1: w³×w-⁶
2: a⁴÷a-²
I need help with both

Answer:
w^-2 = 1/w^2
a^6
Step-by-step explanation:
We know that a^b * a^c = a^( b+c)
w^3 * w^ -5 = w^(3-5) = w^-2
We know that a^-b = 1/a^b
w^-2 = 1/w^2
We know that a^b ÷ a^c = a^( b-c)
a^4 ÷ a^-2 = a^(4 - -2) = a^6
Answer:
[tex]\frac{1}{ w^{2} }[/tex]
[tex]a^{6}[/tex]
Step-by-step explanation:
x^n * x^m = x ^ (n+m)
w^3 * w^ -5 = w^ -2 = [tex]\frac{1}{ w^{2} }[/tex]
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x^n ÷ x^m = x^ n-m
a^4 ÷ a^-2 = a^ 4 -(-2) = [tex]a^{ 6}[/tex]