Please help me with this, thank you.

Hi ;-)
[tex]\frac{2xy}{5ac}:\frac{4xy^2}{15a^2c}=\frac{2xy}{5ac}\cdot\frac{15a^2c}{4xy^2}=\frac{3a}{2y}\\\\Answer: \ \text{D}[/tex]
Answer:
[tex]{ \underline{ \sf{D. \: \: \frac{3a}{2y} }}}[/tex]
Step-by-step explanation:
[tex]{ \sf{ \frac{2xy}{5ac} \div \frac{ {4xy}^{2} }{15 {a}^{2} c} }}[/tex]
find the reciprocal :
[tex]{ \sf{ = \frac{2xy}{5ac} \times \frac{15 {a}^{2}c }{4 {xy}^{2} } }} \\ \\ = { \sf{( \frac{2xy}{4 {xy}^{2} }) \times ( \frac{15 {a}^{2}c }{5ac} ) }} \\ \\ = { \sf{ \frac{1}{2y} \times 3a}} \\ \\ = { \sf{ \frac{3a}{2y} }}[/tex]