Answer:
B. [tex] = 16 {x}^{12} [/tex]
Step-by-step explanation:
[tex](2 {x}^{3} {)}^{4} [/tex]
➡️ [tex] {2}^{4} \times ( {x}^{3} {)}^{4} [/tex]
➡️ [tex]2 \times 2 \times 2 \times 2[/tex] [tex] = 16[/tex]
➡️ [tex]16 \times ( {x}^{3} {)}^{4} [/tex]
➡️ [tex]( {x}^{3} {)}^{4} [/tex]
➡️ [tex] {x}^{3 \times 4} = {x}^{12} [/tex]
➡️ B. [tex] = 16 {x}^{12} [/tex] ✅
