The emu was running at a speed of 14.58 m/s when he was tired.
To solve this question, we'll begin by calculating the distance travelled in the first part of the trip. This can be obtained as follow:
Time (t₁) = 5 min = 5 × 60 = 300 s
Speed 1 (S₁) = 20 m/s
Distance 1 (d₁) =?
Speed = distance / time
S₁ = d₁ / t₁
20 = d₁ / 300
Cross multiply
d₁ = 20 × 300
Distance 1 (d₁) = 6000 m
Next, we shall determine the total distance travelled by the emu.
Average speed = 15 m/s
Time 1 (t₁) = 300 s
Time 2 (t₂) = 1 h = 60 mins = 60 × 60 = 3600 s
Total time (T) = t₁ + t₂ = 300 + 3600 = 3900 s
Total distance (D) =?
Average speed = Total distance / total time
15 = D / 3900
Cross multiply
D = 15 × 3900
Total distance (D) = 58500 m
Next, we shall determine the distance travelled in the second part (i.e when he was tired) of the trip.
Total distance (D) = 58500 m
Distance 1 (d₁) = 6000 m
Distance 2 (d₂) =?
D = d₁ + d₂
58500 = 6000 + d₂
Collect like terms
58500 – 6000 = d₂
Distance 2 (d₂) = 52500 m
Finally, we shall determine the speed of the emu in the second part of the trip.
Distance 2 (d₂) = 52500 m
Time 2 (t₂) = 3600 s
Speed 2 (S₂) =?
Speed = distance / time
S₂ = 52500 / 3600
S₂ = 14.58 m/s
Therefore, the emu was running at a speed of 14.58 m/s when he was tired.
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