contestada

Find three consecutive even integers such that five times the second is six more than twice the sum
of the first and third integers

Respuesta :

Answer:

The first number = 4

The second number = 6

The third number = 8

Step-by-step explanation:

Let all unknown numbers be represented by the variable x.

So;

x = first number

x + 2 = second number

x + 4 = third number

placing in a form as demanded by the question.

5(x + 2) = 6 + 2x + 2 ( x + 4)

5x + 10 = 6 + 2x + 2x +8

5x - 4x = 14 - 10

x = 4

Therefore;

The first number (x) = 4

The second number ( x + 2) = 4 + 2 = 6

The third number (x + 4) = 4 + 4 = 8

wolf1728

Answer:

2x + 2x +2 + 2x +4 = 6x +6 =Sum

5 * (2x +2) = 2 * (2x + 2x +4) +6

10x + 10 = 8x + 8 + 6

2x = 4

x = 2

So the numbers are:

2x or 4

2 x + 2 = 6

2x + 4 = 8

Double-Check

5 * 2nd integer = 30

2 *  (1st + 3rd integers) = 24

30 is 6 more than 24

Success!!!

Step-by-step explanation: