The area of a rectangle is 52 inches if the length is two times the width find the dimensions of the rectangle round off your answer to the nearest hundredth

Respuesta :




A=52in
Length= 2x
Width=x

Length(Width)= Area

2x^2=52
Divide both side by two
x^2=26
Sqrt both side
x=+ or - sqrt(26)

Length=2(sqrt(26)=2sqrt(26) or 10.20

Width=sqrt(26) or 5.20

Answer:

about 5.10 by 10.20 inches

Step-by-step explanation:

You can substitute the width for "x"

This would make the length 2x as it is two times the width

Area in a rectangle is Length times Width, so in this case it would be 2x * x

It gives you the area as 52 inches, so you can substitute this in the equation making it 52 = 2x^2

divide by two on both sides: 26 = x^2

take the square root of both sides, and x is 5.0999

Now to find the length, just double it, which rounds out to 10.20

5.0999 rounds to the hundredth as 5.10

so for dimensions you have 5.10 by 10.20