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A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of
the car (assume uniform acceleration).

Respuesta :

neaa307

Answer:

57.12 m

Step-by-step explanation:

velocity= distance/time

distance= velocity×time

=22.4×2.55

=57.12 m

Answer:

d = 28.6 m

Step-by-step explanation:

Given:

vi = 22.4 m/s

vf = 0 m/s

t = 2.55 s

Find:

d = ??

d = (vi + vf)/2 *t

d = (22.4 m/s + 0 m/s)/2 *2.55 s

d = (11.2 m/s)*2.55 s

d = 28.6 m

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