The time that takes for the train that is traveling with an initial velocity of 20.1 m/s to stop is 402 seconds.
The time that will take for the train to stop can be calculated with the following kinematic equation:
[tex] v_{f} = v_{i} + at [/tex] (1)
Where:
[tex] v_{f}[/tex]: is the final velocity = 0 (when it stops)
[tex] v_{i}[/tex]: is the intial velocity = 20.1 m/s
a: is the acceleration = -0.0500 m/s²
t: is the time =?
By solving equation (1) for t, we have:
[tex] t = \frac{v_{f} - v_{i}}{a} = \frac{0 - 20.1 m/s}{-0.0500 m/s^{2}} = 402 s [/tex]
Therefore, it will take 402 seconds for the train to stop.
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I hope it helps you!
