a. The ball's velocity after 0.24 s is 0.75 m/s
b. The acceleration of the ball is given by the acceleration due to gravity
a. The ball's velocity can be calculated with the following equation:
[tex] v_{f} = v_{0} - gt [/tex]
Where:
[tex] v_{f} [/tex]: is the final speed =?
[tex]v_{0}[/tex]: is the initial speed = 3.1 m/s
g: is the acceleration due to gravity = 9.81 m/s²
t: is the time = 0.24 s
The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).
The final speed is:
[tex] v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s [/tex]
Hence, the ball's velocity after 0.24 s is 0.75 m/s.
b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.
You can see another example of velocity here: https://brainly.com/question/13388351?referrer=searchResults
I hope it helps you!
