Respuesta :
Answer:
2NaOH + CO2 -> Na2CO3 + H2O
1) Find the moles of each substance
[tex]\eq n(NaOH)=\frac{35.0}{22.99+16.00+1.008\\}\ =\frac{35.0}{39.998} \ = 0.8750437522 moles\\n(CO_{2} ) = \frac{17.5}{12.01+32.00} = \frac{17.5}{44.01} = 0.3976369007 moles\\[/tex]
2) Determine the limitting reagent
[tex]\\NaOH = \frac{0.8750437522}{2} = 0.4375218761\\\\[/tex]
∴ Carbon dioxide is limitting as it has a smaller value.
3) multiply the limiting reagent by the mole ratio of unknown over known
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
4) Multiply the number of moles by the molar mass of the substance.
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g
Explanation:
The correct answer is = 3.581913202 g.
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g.
What does H2O stand for?
H2O is the molecular formula of water, also called Dihydrogen monoxide. H2O symbolises two hydrogen atoms and one oxygen atom.
What is 1 mol H2O?
Water (H2O) is made from 2 atoms of hydrogen and 1 atom of oxygen. A mole of water molecules would be 2 moles of hydrogen atoms plus 1 mole of oxygen atoms. From the periodic table, we see the atomic weight of hydrogen is 1.0079 and the atomic weight of oxygen is 15.9994.
Learn more about What is 1 mol H2O? here: https://brainly.com/question/2003415
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