Answer:
[tex]\displaystyle y = -6x + 5[/tex]
Where ? = -6.
Step-by-step explanation:
We want to find the equation of a line that is perpendicular to:
[tex]\displaystyle y = \frac{1}{6} x + 3[/tex]
And contains the point (-3, 23).
Recall that the slopes of perpendicular lines are negative reciprocals of each other.
The negative reciprocal of 1/6 is -6. Hence, the slope of the perpendicular line is -6.
We are also given that it passes through the point (-3, 23). Since we know the slope and a point, we can consider using the point-slope form:
[tex]\displaystyle y - y_1 = m(x - x_1)[/tex]
Substitute:
[tex]\displaystyle y - (23) = -6(x - (-3))[/tex]
Simplify:
[tex]\displaystyle y - 23 = -6 (x+3)[/tex]
Distribute:
[tex]\displaystyle y - 23 = -6x - 18[/tex]
And add. Hence:
[tex]\displaystyle y = -6x + 5[/tex]
In conclusion, our equation is:
[tex]\displaystyle y = -6x + 5[/tex]
Where ? = -6.
