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Time of flight of projectile launched horizontally
An object of mass 5 kg is projected horizontally with a speed of 24.4 ms-1 from the top of the cliff. The height of the cliff
is 21.2 m. Take g, the acceleration due to gravity, to be 9.8 ms-2.
The object is in flight for

Respuesta :

Answer:

t = 2.1 s

Explanation:

We only need to find the time needed for the projectile to fall 21.2 m from vertical rest.

s = ½at²

21.2 = ½(9.8)t²

t = √(2(21.2)/9.8) = 2.080031396...

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