Answer:
y = - 4x + 11
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
x - 4y = 12 ( subtract x from both sides )
- 4y = - x + 12 ( divide terms by - 4 )
y = [tex]\frac{1}{4}[/tex] x - 3 ← in slope- intercept form
with slope m = [tex]\frac{1}{4}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{4} }[/tex] = - 4 , then
y = - 4x + c ← is the partial equation
To find c substitute 2, 3 ) into the partial equation
3 = - 8 + c ⇒ c = 3 + 8 = 11
y = - 4x + 11 ← equation of perpendicular line
The equation y + 4x = 11 is the equation of a line that is perpendicular to the line x-4y = 12 and passes through the point (2,3).
By rearranging x - 4y = 12 in the form, y = mx + c;
we have; y = (x/4) - 3
The slope, m1 from here is (1/4)
The product of the slopes of two perpendicular lines is;
Therefore, the equation of the line whose slope is -4 and passes through the point (2,3) is;
By cross product; we have;
y + 4x = 11.
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