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A baseball team won 16 games and lost 11. At this rate, how many games will it win in a 162-game schedule?

Respuesta :

Answer:  96

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Explanation:

The team won 16 games and lost 11 so far. At this point in the season, they played 16+11 = 27 games total. Their win rate is 16/27.

Set this equal to x/162 which is the win rate for winning x games out of 162 played over the entire season.

Solve for x.

x/162 = 16/27

27x = 162*16 ... cross multiplication

27x = 2592

x = 2592/27

x = 96

The team would win 96 games if it kept the same winning rate going.

Notice that 16/27 = 0.5926 = 59.26% and how 96/162 = 0.5926 = 59.26% as well (both are approximate). This helps confirm we have the correct answer.

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Here's another slightly longer way to solve. If you prefer the first method above, then ignore this section.

w = number of games won over the entire 162 game season

162-w = number of games lost over the entire season

w/(162-w) = win to loss ratio

16/11 = win to loss ratio after winning 16 games and losing 11

Setting those last two expressions equal to each other and solving for w gets us...

w/(162-w) = 16/11

11w = 16(162-w)

11w = 2592-16w

11w+16w = 2592

27w = 2592 ... this hopefully looks a bit familiar from before

w = 2592/27

w = 96 games won

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