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Ms. Hawkins is taking her science classes on a field trip to a museum. She has $ 1,900 spend on the trip. The bus company will charge $ 175 for travel. The museum charges $6.50 for admission per student and $ 2.25 for lunch per student. Ms. Hawkins gets free admission and lunch. Let s represent the number of students that could go on the trip while Ms. Hawkins stays within her budget .

Write an inequality that models this situation.

Determine how many students Ms. Hawkins can bring with her on her field trip and stay in her budget.

Respuesta :

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The inequality is ;

  • 175 + 6.50s + 2.25s ≤ 1900
  • Number of students = 197

Total amount to spend = $1900

Bus charge = $175

Admission fee per student = $6.50

Lunch fee per student = $2.25

Number of students = s

Writing out the total cost :

Bus charge + (admission fee × s) + (lunch fee × s) ≤ 1900

175 + 6.50s + 2.25s ≤ 1900

Using the equation defined, we can find s ;

175 + 6.50s + 2.25s ≤ 1900

Solve for s

8.75s ≤ 1900 - 175

8.75s ≤ 1725

s ≤ 1725 / 8.75

s ≤ 197.14

The number of students she can bring along is 197 and still stay within her budget.

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