girliedecastro26
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HELP ASAP pleaseeee

Solve for x, 3y = z - 2x

please also explain the steps you did to get the answer. it doesn't have to be a long explanation. just enough so I understand

Respuesta :

[tex]\\ \sf\longmapsto 3y=z-2x[/tex]

  • Take z to left

[tex]\\ \sf\longmapsto -2x=3y-z[/tex]

  • Take out -

[tex]\\ \sf\longmapsto 2x=-3y+z[/tex]

[tex]\\ \sf\longmapsto 2x=z-3y[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{z-3y}{2}[/tex]

Hi1315

Answer:

[tex] x = \frac{z - 3y}{2} [/tex]

Step-by-step explanation:

Question :

[tex]3y = z - 2x[/tex]

First take 2x to the left to make the 2x as a positive number (So, It's easy to solve)

[tex]3y + 2x = z[/tex]

Then take 3y to the right side

[tex]2x = z - 3y[/tex]

Now, divide both sides by 2 to make the x as the Subject

[tex] \frac{2x}{2} = \frac{z - 3y}{2} \\ x = \frac{z - 3y}{2} [/tex]

hope this helps you.

Please let me know if you have another questions :-)

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