Using the concept of anti logarithm, from an example given, it is found that the antilog of 0.3712 is 2.3507.
-------------------
[tex]x = \text{antilog}_by[/tex] means that [tex]x = b^y[/tex]
[tex]\text{antilog} 0.3712 = 10^{0.3712} = 2.3507[/tex]
A similar problem is given at https://brainly.com/question/16636033