In the reaction of 12.7 grams of copper with 3.2 grams of sulfur to form copper sulfide, the amount of copper sulfide produced is 15.9 grams.
The reaction between copper and sulfur to form copper sulfide is:
2Cu + S → Cu₂S
According to the law of conservation of mass, in a chemical reaction, the sum of the masses of the reactants must be equal to the sum of the masses of the products, since matter can not be created or destroyed, it only can be transformed.
Hence, the mass of copper sulfide can be calculated as follows:
[tex] m_{Cu} + m_{S} = m_{CuS} [/tex]
[tex] 12.7 g + 3.2 g = m_{CuS} [/tex]
[tex] m_{CuS} = 15.9 g [/tex]
Therefore, the mass of copper sulfide produced is 15.9 grams.
To learn more about the law of conservation of mass, go here: https://brainly.com/question/14236219?referrer=searchResults
I hope it helps you!
