dgarcia27610
contestada

Consider the line y=-7/5x+3

Find the equation of the line that is parallel to this line and passes through the point (-7,4).

Find the equation of the line that is perpendicular to this line and passes through the point (-7,-4).

Respuesta :

Answer:

Given:  y=(-7/5)x+3        [y=mx+b, where slope,m, is -7/5]

  All parallel lines have same slope, m=-7/5,

   so their formulas look like:  y=(-7/5)x + b and we need a point to determine b. Use (-5,4).

     4 = (-7/5)(-5) + b

     4 = 7 + b

     -3 = b

The parallel line is:     y = (-7/5)x - 3

Check (important) that point (-5,4) is on the line:

   Does 4 = (-7/5)(-5) - 3   ?

           4 = 7 - 3   ?

           4 = 4   ?yes

Otras preguntas