A stream consisting of 48.9 mole% benzene (B) and 51.1% toluene (T) is fed at a constant rate to a process unit that produces two product streams, one a vapor and the other a liquid. The vapor flow rate is initially zero and asymptotically approaches one third of the molar flow rate of the feed stream. Throughout this entire period, no material accumulates in the unit. When the vapor flow rate has become constant, the liquid is analyzed and found to be 28.0 mole% benzene.

Required:
How would you expect the vapor flow rate to vary with time?

Question

22-09-2021
Chemistry

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A stream consisting of 48.9 mole% benzene (B) and 51.1% toluene (T) is fed at a constant rate to a process unit that produces two product streams, one a vapor and the other a liquid. The vapor flow rate is initially zero and asymptotically approaches one third of the molar flow rate of the feed stream. Throughout this entire period, no material accumulates in the unit. When the vapor flow rate has become constant, the liquid is analyzed and found to be 28.0 mole% benzene.

Required:
How would you expect the vapor flow rate to vary with time?

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batolisis batolisis · Answer 1 · 2021-09-27T11:07:35+02:00

The vapor flowrate will vary with time by ; gradually increasing from zero to one half of the molar feed flow rate and then remain constant ( C )

Although the options related to your question is missing attached below are the missing options

Vapor flow rate is the amount of vapor per unit of time that flows through a specific area at a given time .

Given that the stream consists of 48.9 mole% of benzene and 51.1% toluene fed at a constant rate into a process unit. The vapor flowrate will vary with time because it will gradually increase from zero to 1/2 of the molar feed flow rate before it will remain constant.

Hence we can conclude that The vapor flowrate will vary with time by gradually increasing from zero to one half of the molar feed flow rate and then remain constant.

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