Answer:
[tex]x^a*x^b =x^{a+b}[/tex]
[tex](x^a)^b=x^{a*b}[/tex]
[tex]\frac{x^a}{x^b}=x^{a-b}[/tex]
[tex]x^{-a} =\frac{1}{x^a}[/tex]
[tex]x^0=1[/tex]
Step-by-step explanation:
1) When 2 variables with the same bases are multiplied their exponents are added. So, x^2 * x^3 = x^5.
2) When a variable is being to 2 different powers at the same time the exponents should be multiplied. Therefore, (x^2)^3 = x^6.
3) When dividing variables with the same term the exponents should be subtracted. This means x^3/x^2 = x^1 or just x.
4) Negative exponents are not considered standard form. So, to make the exponents positive find the reciporcal. The variable x^-2 would be equal to 1/x^2
5) The zero exponent rule states that any non-zero number raised to the power of 0 is 1. Thus, 2^0 = 1.
