If the figure below is rotated 90 degrees counter-clockwise, what is the radius of the circle that has
a center at (0, 0) and intersects both F and F?
A-8
B-4
C-6
D-2

If the figure below is rotated 90 degrees counterclockwise what is the radius of the circle that has a center at 0 0 and intersects both F and F A8 B4 C6 D2 class=

Respuesta :

When a shape is rotated, it must be rotated through a point.

The radius of the circle is: 4

The location of point F is:

[tex]F = (4,0)[/tex]

When the shape is rotated [tex]90^o[/tex] counterclockwise, the rule is:

[tex](x,y) \to (-y,x)[/tex]

So, the location of point F' is:

[tex]F' = (0,4)[/tex]

The center of the circle is given as:

[tex]O = (0,0)[/tex]

The radius of the circle is the distance from the center to point F or F'

This is calculated using the following distance formula

[tex]d =\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

The distance from O to F is:

[tex]r =\sqrt{(0 - 4)^2 + (0 - 0)^2}[/tex]

[tex]r =\sqrt{16 + 0}[/tex]

[tex]r =\sqrt{16}[/tex]

Take square roots

[tex]r = \±4[/tex]

Radius cannot be negative.

So:

[tex]r = 4[/tex]

Hence, the radius of the circle is (b) 4

Read more about rotation at:

https://brainly.com/question/1571997