Abe digs a hole at a steady rate of 1 2/3 feet every hour. Consider ground level to be 0. What value represents the elevation of the hole relative to ground level after digging for 2 1/2 hours? Enter your answer as a simplified mixed number in the box.

Respuesta :

Length of hole digging for [tex]2\frac{1}{2}[/tex] hours is 4.167 feet.

Given that;

Rate of digging hole by Abe = [tex]1\frac{2}{3}[/tex] feet every hour

Find:

Length of hole digging for [tex]2\frac{1}{2}[/tex] hours

Computation:

Rate of digging hole by Abe = [tex]1\frac{2}{3}[/tex] feet every hour = 5/3 feet every hour

Time taken =  [tex]2\frac{1}{2}[/tex] hours = 5/2 hours

Length of hole digging for [tex]2\frac{1}{2}[/tex] hours = Rate of digging hole by Abe × Time taken

Length of hole digging for [tex]2\frac{1}{2}[/tex] hours = (5/3)(5/2)

Length of hole digging for [tex]2\frac{1}{2}[/tex] hours = 25 / 6

Length of hole digging for [tex]2\frac{1}{2}[/tex] hours = 4.167 feet (Approx.)

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