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What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the box moves is 17m and the force applied is 38 N?

Respuesta :

hamzaahmeds

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

[tex]Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd[/tex]

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

[tex]E = (0.4)(38\ N)(17\ m)[/tex]

E = 258.4 J

Learn more about friction energy here:

https://brainly.com/question/1343045?referrer=searchResults

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