Josuahja
contestada

a cart the weight 20 kg is rolling down a hill with a velocity of 4.2m/s. what is the kinetic energy of the cart.​

Respuesta :

  • Mass=m=20kg
  • Velcocity=v=4.2m/s^2

[tex]\\ \sf\longmapsto K.E=\dfrac{1}{2}mv^2[/tex]

[tex]\\ \sf\longmapsto K.E=\dfrac{1}{2}(20)(4.2)^2[/tex]

[tex]\\ \sf\longmapsto K.E=10(17.64)[/tex]

[tex]\\ \sf\longmapsto K.E=176.4J[/tex]

Hi1315

Answer:

[tex]176.4J[/tex]

Explanation:

Formula to find the kinetic energy is,

[tex]E_{k} = \frac{1}{2} m {v}^{2} [/tex]

Let's solve now

[tex]E _{k} = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} \times 20kg \times 4.2 m {s}^{ - 1} \times 4.2 {ms}^{ - 1} \\ = \frac{352.8}{2} \\ = 176.4J[/tex]

Hope this helps you.

Let me know if you have any other questions :-)

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