chandraghimire320
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A closed cylinder is filled with CO₂ gas. The mass of CO₂ in cylinder is 4.4 g. Now express this amount of Carbon dioxide in following terms:
a) no. of moles of CO₂ molecules
b) Volume at NTP
c) No. of 'gram molecule
d) No. of CO₂ molecules
e) No. of carbon atoms
f) No. of mole of Oxygen atoms
g) No. of molecules of oxygen​

Respuesta :

#a

Molar mass of CO2=44g/mol

given mass=4.4g

[tex]\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\;Mass}=\dfrac{4.4}{44}=0.1mol[/tex]

#b

  • At NTP 1mol weigh 22.4L

0.1mol weigh:-

[tex]\\ \sf\longmapsto 22.4(0.1)=2.24L[/tex]

#c

No of molecules=Moles×Avagradro No

[tex]\\ \sf\longmapsto 0.1\times 6.023\times 10^{22}=6.023\times 10^{21}molecules[/tex]

#d

  • CO_2 has 3atoms

No of molecules=

[tex]\\ \sf\longmapsto 3\times 6.023\times 10^{21}=18.069\times 10^{21}molecules[/tex]

#e

  • CO2 has 1carbon

[tex]\\ \sf\longmapsto No\:of\:molecules=6.023\times 10^{21}molecules[/tex]

#f

Lets write balanced equation

[tex]\\ \sf\longmapsto C+O_2=CO_2[/tex]

  • 1mol of Oxygen exists

#g

It has 2oxygen atoms

[tex]\\ \sf\longmapsto No\:of\:molecules=2(6.023\times 10^{21})=12.046\times 10^{21}[/tex]

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