A grasshopper of mass 0.12 g jumps vertically. It uses its back legs over a time of 0.020s to jump,
leaving the ground with a velocity of 3.0 ms.
What is the average power developed by the legs of the grasshopper?
A 9.0 x 10-'W
B
1.8 x 10-2W
с
2.7 x 10-2W
D 37 W

Respuesta :

Answer:

P = (1/2 * m * V ^ 2)/t = 1/2 * ((0.12 * 10 ^ - 3) * c)/0.020

= 2.7*10^ -2 w

The average power developed by the legs of the grasshopper will be 2.7 × 10⁻² W.

What is average power?

Average power is a ratio of total work done by the body to the total time. Its unit is the watt.

The given data in the problem is ;

mass (m)=  0.12 g

time to run up = 0.020 s

According to the law of conservation of energy,

Work = change in Potential energy

Power is defined as the rate of work done which is found as;

[tex]\rm P = \frac{W}{t} \\\\ P= \frac{\frac{1}{2}mv^2 }{t} \\\\ P= \frac{\frac{1}{2}(0.12)(10^{-3})(3)^2}{0.020} \\\\P=2.7 \times 10^{-2}\ sec[/tex]

The average power developed by the legs of the grasshopper will be 2.7 × 10⁻² W.

Hence,option C is correct.

To learn more about the average power refer to the link;

https://brainly.com/question/14669681

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