3.24 x 10⁻¹⁹ Joule
Given:
A neon sign with a frequency of 4.89 x 10¹⁴ Hz.
Question:
The energy of the orange light emitted per photon (in joules).
The Process:
The energy of a photon is given by [tex]\boxed{\boxed{ \ E = hf \ }}[/tex]
Let us find out the energy of the orange light emitted per photon.
[tex]\boxed{ \ E = (6.63 \times 10^{-34})(4.89 \times 10^{14}) \ }[/tex]
Thus, we get a result of [tex]\boxed{\boxed{ \ E = 3.24 \times 10^{-19} \ J \ }}[/tex]
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Notes:
Keywords: calculate, the energy of the orange light emitted, per photon, by a neon sign, frequency, Planck's constant
The energy of the orange light emitted, per photon is 3.42 × 10⁻¹⁹J.
Given the data in the question;
Energy of the orange light emitted; [tex]E =\ ?[/tex]
Photon energy is the energy carried by a single photon, represented by the expression:
[tex]E = hf[/tex]
Where:
We substitute our values into the equitation
[tex]E = ( 6.626 * 10^{-34}J/Hz) * ( 4.89 * 10^{14} Hz)\\\\E = 3.24 * 10^{-19}J[/tex]
Therefore, the energy of the orange light emitted, per photon is 3.42 × 10⁻¹⁹J
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