we have
[tex]4x-y=1[/tex]
This is the equation of the line in standard form
so
The graph is a straight line
we are going to proceed to verify the first two cases only
case A) It is a straight line joining the points [tex](0, -1)[/tex], [tex](1, 3)[/tex], and [tex](-1, -5)[/tex]
Using a graphing tool
The three points are on the straight line
see the attached figure N [tex]1[/tex]
case B) It is a straight line joining the points [tex](4,-3)[/tex], [tex](-1, 2)[/tex], and [tex](-4, 5)[/tex]
Using a graphing tool
The three points are not in the straight line
see the attached figure N [tex]2[/tex]
therefore
the answer is
It is a straight line joining the points [tex](0, -1)[/tex], [tex](1, 3)[/tex], and [tex](-1, -5)[/tex]