Respuesta :
The formula is 1.5RT, where R is the universal gas constant and T is the temperature in kelvin.
1.5(8.314 J/molK)(0+273.15)K(1 mol) = 3406J
1.5(8.314 J/molK)(0+273.15)K(1 mol) = 3406J
Answer:
Average kinetic energy of 1 mole of a gas at 0 K is around 2780 J
Explanation:
Kinetic energy is the energy of motion. Based on the kinetic theory of gases, the average kinetic energy (KE) is directly proportional to the temperature (T) of the gas particles.
[tex]KE = \sqrt{3/2} RT\\[/tex]
where R = gas constant
T = temperature in Kelvin
Therefore, at T = 0 C i.e. (0 + 273)K = 273 K
[tex]KE = \sqrt{3/2} *8.314 J/mol-K * 273 K = 2779.8 J[/tex]
The average kinetic energy is 2779.8 J