Answer:
n ≥ − the quantity 3 times c minus 9 all over p
Step-by-step explanation:
To solve inequalities you should use the same method as to solve equalities.
1. First write down the inequality:
[tex]-np-6\leq 3(c-5)[/tex]
2. Solve the parentheses:
[tex]-np-6\leq 3c-15[/tex]
3. Pass the independent numbers to the right side of the inequality with opposite sign and do the mathematical operations:
[tex]-np\leq 3c-15+6\\\\-np\leq 3c-9[/tex]
4. Pass the p with the minus sign to the right side of the inequality, as p has the minus sign, the direction of the inequality changes:
[tex]n\geq -(\frac{3c-9}{p})[/tex]
