Below are two different functions, f(x) and g(x). What can be determined about their y-intercepts?
(A) The function f(x) has a higher y-intercept.

(B) The function g(x) has a higher y-intercept.

(C) They both have the same y-intercept.

(D) The relationship between y-intercepts cannot be determined.

Below are two different functions fx and gx What can be determined about their yintercepts A The function fx has a higher yintercept B The function gx has a hig class=

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diene
f(x) = 4x-1, so the y-intercept is 4(0)-1 = -1
g(x) = x+2, so the y-intercept is (0)+2= 2
(B) The function g(x) has a higher y-intercept.

we have that

[tex]f(x)=4x-1[/tex]

In the table

Let

[tex]A(1,3)\\B(4,6)\\C(7,9)[/tex]

Step [tex]1[/tex]

Find the equation of the line of g(x)

Find the slope AB

slope m is equal to

[tex]m=\frac{(y2-y1)}{(x2-x1)}[/tex]

[tex]m=\frac{(6-3)}{(4-1)}[/tex]

[tex]m=1[/tex]

with the slope m and the point [tex]A(1,3)[/tex] find the equation of the line

[tex]y-y1=m(x-x1)[/tex]

[tex]y-3=1*(x-1)[/tex]

[tex]y=x-1+3[/tex]

[tex]y=x+2[/tex]

[tex]g(x)=x+2[/tex]

Step [tex]2[/tex]

Find the y-intercept of f(x) and g(x)

we know that

the y-intercept is the value of the y-coordinate when the value of x is equal to zero

[tex]f(x)=4x-1[/tex]

for [tex]x=0[/tex]

[tex]f(x)=4*0-1[/tex]

[tex]f(x)=-1[/tex]

the y-intercept of f(x) is equal to [tex]-1[/tex]

[tex]g(x)=x+2[/tex]

for [tex]x=0[/tex]

[tex]g(x)=0+2[/tex]

[tex]g(x)=2[/tex]

the y-intercept of g(x) is equal to [tex]2[/tex]

therefore

the answer is the option

(B) The function g(x) has a higher y-intercept