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What is the equation of the plane that contains the triangle shown in the diagram?


2x + 3y + z = 6

2x + 3y + 6z = 12

3x + 2y + 6z = 0

6x + 2y + 3z = 18

What is the equation of the plane that contains the triangle shown in the diagram 2x 3y z 6 2x 3y 6z 12 3x 2y 6z 0 6x 2y 3z 18 class=

Respuesta :

the first equation

2x + 3y + 6z = 12

Answer:

Option A is correct.

[tex]2x + 3y +z = 6[/tex]

Step-by-step explanation:

The intercept form of the equation of plane is given by:

[tex]\frac{x}{l}+\frac{y}{m} +\frac{z}{n} =1[/tex]            .....[1]

where

l is the intercept of x-axes

m is the intercept of y-axes and

n is the intercept of z-axes respectively;

From the given figure;

we have;

The intercepts of coordinates axes are;

[tex]l = 3[/tex]

[tex]m = 2[/tex]

[tex]n = 6[/tex]

Substitute these values in the equation [1]; we have;

[tex]\frac{x}{3}+\frac{y}{2} +\frac{z}{6} =1[/tex]  

Taking LCM of 3, 2 and 6 is 6

[tex]2x + 3y +z = 6[/tex]

therefore, the equation of plane that contains the triangle as shown in the diagram is, [tex]2x + 3y +z = 6[/tex]