Respuesta :
pH= log[H3O+]
10.25=log [H3O+]
[H3O+] = 10^10.25
[H3O+]= 1.778 ×10^10
10.25=log [H3O+]
[H3O+] = 10^10.25
[H3O+]= 1.778 ×10^10
pH + pOH = 14
10.25 + pOH = 14
pOH = 14 - 10.25 = 3.75
Now, knowing the pOH we can find the OH^- since pOH is -log [OH-]
[OH-] = 10^-3.75 = 1.78x10^-4 M