Answer:
The average atomic mass of vitellium is 192.11 amu.
Explanation:
The average atomic mass is an average between the masses of all the isotopes, considering their abundance in the nature. It can be calculated using the following expression:
[tex]AAM=\frac{\Sigma m_{i} \times ab_{i} }{100}[/tex]
where,
[tex]m_{i}[/tex] is the mass of each isotope.
[tex]ab_{i}[/tex] is the abundance in the nature of each isotope.
For vitelium,
[tex]AAM=\frac{187.9122amu \times 10.861 + 190.9047amu \times 12.428 + 192.8938 amu\times 76.711 }{100} =192.11amu[/tex]
