The velocity of the ball after it hits the bottle is 15.8 m/s
Let m₁ represent the mass of the ball, m₂ the mass of the bottle, u₁ the velocity of ball before impact, u₂ the velocity of bottle before impact, v₁ the velocity of ball after impact and v₂ the velocity of bottle after impact.
Given that:
m₁ = 0.7 kg, m₂ = 0.15 kg, u₁ = 22 m/s, u₂ = 0, v₂ = 29
momentum before impact = momentum after impact, hence:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.7(22) + 0.15(0) = 0.7v₁ + 0.15(29)
0.7v₁ = 11.05
v₁ = 15.8 m/s
Therefore the velocity of the ball after it hits the bottle is 15.8 m/s
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