Henry is at the state fair. At one booth he throws a 0.70 kg ball forward with a velocity of 22.0 m/s in order to hit a 0.15 kg bottle sitting on a shelf. When the ball makes contact the bottle goes flying forward at 29.0 m/s. What is the velocity of the ball after it hits the bottle?

Respuesta :

The velocity of the ball after it hits the bottle is 15.8 m/s

Let m₁ represent the mass of the ball, m₂ the mass of the bottle, u₁ the velocity of ball before impact, u₂ the velocity of bottle before impact, v₁ the velocity of ball after impact and v₂ the velocity of bottle after impact.

Given that:

m₁ = 0.7 kg, m₂ = 0.15 kg, u₁ = 22 m/s, u₂ = 0, v₂ = 29

momentum before impact = momentum after impact, hence:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.7(22) + 0.15(0) = 0.7v₁ + 0.15(29)

0.7v₁ = 11.05

v₁ = 15.8 m/s

Therefore the velocity of the ball after it hits the bottle is 15.8 m/s

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