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How many cm of a solution of 0.100 mol dm NaOH are required to completely -3 neutralize 25.0 cm of 0.250 mol dm H3PO4?. a) Write a balanced equation for the reaction (4 marks) b) How many moles of H3PO4 need to be neutralized? (1 marks) c) How many moles of NaOH are needed to neutralize the H3PO4? (1 marks) d) How many cm of 0.100 mol dm NaOH contain the moles in question 5(©) above? (1 marks) ​

Respuesta :

Answer:

Explanation:

How many cm of a solution of 0.100 mol dm NaOH are required to completely  neutralize  25.0 cm of 0.250 mol dm H3PO4?.

a) Write a balanced equation for the reaction NaOH to neutralize (4 marks

?. ) 25.0 cm of 0.250 mol dm H3PO4

H3PO4 + 3NaOH----------> Na3PO4 +3 H2O

b) How many moles of H3PO4 need to be neutralized? (1 marks)

25.0 cm3 of 0.250 mol dm3 H3PO4: 1 liter has 0.25 moles. 100 ml has 0.025 moles 25 ml has o.025/4 molea or 0.00625 moles)

c How many moles of NaOH are needed to neutralize the H3PO4? (1 marks)

for every moles of H3PO4, WE NEED 3 MOLES OF NaOH.  FOR 0.00625 MOLES WE NEED 3X 0.00625 =0.01875 MOLES OF NaOH

d) How many cm3 of 0.100 mol /l NaOH contain the moles in question 5(©) above? (1 marks)

1 L CONTAINS 0.100 Moles

100 ml contains 0.010Moles

we need 187.5 ml since (187.5 X 0.100)/1000=0.01875

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