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A projectile is launched with an initial speed of 12 m/s. At its highest point its speed is 6 m/s. What was the launch angle of the projectile?

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facundo3141592

We want to find at what angle a projectile is launched given that at the highest point, the speed is 6m/s.

The launch angle of the projectile is 60°.

Remember that the only acceleration will appear on the vertical axis, and this is the gravitational acceleration, this means that on the horizontal axis we will have a constant speed.

Also remember that when an object is on its highest point, the vertical velocity is equal to zero, then it only has horizontal velocity (which we know it is a constant).

Then we can conclude that the horizontal velocity is equal to 6m/s.

If the angle is measured from the horizontal axis, we will have that the horizontal velocity is a projection on the x-axis of the initial speed, this is:

12m/s*cos(θ) = 6m/s

Now we can solve this for theta.

cos(θ) = (6m/s)/(12 m/s) = 1/2

θ = Acos(1/2) = 60°

The launch angle of the projectile is 60°.

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