Two cyclists start from 98 miles apart and begin racing toward each
other. Three hours later, they have not yet met and the distance between
them is 2 miles. How fast is each of them biking if one bikes 3 mph
slower than the other?

Respuesta :

Answer:

um 18 and 21

Step-by-step explanation:

The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.

Let the speed of one bicyclist=x mph

Let the speed of the other bicyclist=(x+3) mph

Hence:

Speed of one bicyclist:

3x+3(x+3)+2=98

3x+3x+9+2=98

6x=87

Divide both side by 6x

x=87/6

x=14.5 mph

Speed of the other bicyclist:

x+3 mph

14.5 mph+3 mph

=17.5 mph

Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.

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