Answer:
A, B, C
Step-by-step explanation:
Assuming the choices are:
A. [tex](x-2)(x^{4}+3)[/tex]
B. [tex]x^{2} -1[/tex]
C. A+[tex]x^{4} +16[/tex]
D. [tex]\frac{1}{x} +2[/tex]
Put simply, a polynomial in this case will be a function that has at least one variable raised to a power greater than 1.
Choice A already has a variable raised to a power greater than 1 ([tex]x^{4}[/tex]), so no additional manipulation is needed.
Choice B also has a term that is already raised to a power greater than 1 ([tex]x^{2}[/tex]). It is the same for choice C ([tex]x^{4}[/tex]).
Choice D does not have an obvious variable raised to a power greater than 1. When the equation is manipulated it becomes [tex]x^{-1} +2[/tex]. Since -1 is less than 1, choice D is not a polynomial.
